Let *f*(*x*) = *b*^{x}. Then the derivative of *f* has the property that *f* '(*x*) = *f* '(0) *b*^{x}.

Below is the plot of *f*(*x*) = b^{x}, its derivative *f* '(x) = (m) b^{x}, as well as a tangent line at *x* = 0. The tangent line has slope *m* = m, as *f* '(0) = m. Move the slider to change the base. What value of *b* yields *f* '(0) = 1?

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